Y=sin(x+兀/6)cos(兀/3-x)的最小正周期怎么算啊
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![Y=sin(x+兀/6)cos(兀/3-x)的最小正周期怎么算啊](/uploads/image/z/6834748-4-8.jpg?t=Y%3Dsin%EF%BC%88x%2B%E5%85%80%2F6%EF%BC%89cos%EF%BC%88%E5%85%80%2F3%EF%BC%8Dx%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E6%80%8E%E4%B9%88%E7%AE%97%E5%95%8A)
Y=sin(x+兀/6)cos(兀/3-x)的最小正周期怎么算啊
Y=sin(x+兀/6)cos(兀/3-x)的最小正周期怎么算啊
Y=sin(x+兀/6)cos(兀/3-x)的最小正周期怎么算啊
Y=sin(x+兀/6)cos(兀/3-x)
=sin(x+兀/6)cos(x+兀/6)
=1/2sin(2x+π/3)
所以最小正周期2π/2=π
Y=sin(x+兀/6)sin(兀/6+x)
=sin(x+兀/6)的平方
=[ 1-cos(2x+兀/3) ]/2
最小正周期=2兀/2=兀
Y=sin(x+兀/6)cos(兀/3-x)
=sin(x+π/6)sin(π/6+x)
=sin²(x+π/6)
=[1-cos(2x+π/3)]/2
=(1/2)cos(2x+π/3)-1/2
所以
最小正周期为 2π/2=π
Y
=sin(x+兀/6)cos(兀/3-x)
=sin(x+π/6)sin(x+π/6)
=1/2(1-cos(2x+π/3))
最小正周期=2π/2=π
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