数学题(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法亲们,求求你们了10财富
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![数学题(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法亲们,求求你们了10财富](/uploads/image/z/755390-38-0.jpg?t=%E6%95%B0%E5%AD%A6%E9%A2%98%28a%2B3a%2B5a%2B%E2%80%A6%2B2003a%29+-+%282a%2B4a%2B6a%2B%E2%80%A6%2B2004a%29%E8%A7%A3%E6%B3%95%28a%2B3a%2B5a%2B%E2%80%A6%2B2003a%29+-+%282a%2B4a%2B6a%2B%E2%80%A6%2B2004a%29%E8%A7%A3%E6%B3%95%E4%BA%B2%E4%BB%AC%2C%E6%B1%82%E6%B1%82%E4%BD%A0%E4%BB%AC%E4%BA%8610%E8%B4%A2%E5%AF%8C)
数学题(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法亲们,求求你们了10财富
数学题(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法
(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法
亲们,求求你们了
10财富
数学题(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)解法亲们,求求你们了10财富
(a+3a+5a+…+2003a) - (2a+4a+6a+…+2004a)
= (a - 2 a)+ (3 a - 4 a)+ (5 a - 6 a)…… + (2003 a - 2004 a)
= (a - 2 a)× 2004 ÷ 2
= - a × 1002
= - 1002 a
a和-2a消掉得 -a,以此类推,总共有1002对,∴-a×1002=-1002a
原式=-(2004a-2003a)-(2002a-2001a)-......-(4a-3a)-(2a-a)
=-2004/2 a
=-1002a
前后一一对应,得
=(-a)+(-a)+(-a)+······+(-a)
=-1002a
= a-2a+3a-4a........+2003a-2004a
=-a-a.......-a
=-1002a
可以看出,减数部分中每一项都比被减数中对应项大a,有多少项就大多少个a,2004/2=1002,所以有1002项,所以最好答案是:-1002a
= a-2a+3a-4a........+2003a-2004a
=-a-a.......-a
=-1002a
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