f(x)=sin^2wx+√s sinwxsin(wx+π/2) (w>0) 最小正周期为π.1)求w值;2)求函数f(x)在[0,2π/3]上值域√3~不好意思~打错了
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![f(x)=sin^2wx+√s sinwxsin(wx+π/2) (w>0) 最小正周期为π.1)求w值;2)求函数f(x)在[0,2π/3]上值域√3~不好意思~打错了](/uploads/image/z/7798350-30-0.jpg?t=f%28x%29%3Dsin%5E2wx%2B%E2%88%9As+sinwxsin%28wx%2B%CF%80%2F2%29+%28w%3E0%29+%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80.1%EF%BC%89%E6%B1%82w%E5%80%BC%EF%BC%9B2%29%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%5B0%2C2%CF%80%2F3%5D%E4%B8%8A%E5%80%BC%E5%9F%9F%E2%88%9A3%7E%E4%B8%8D%E5%A5%BD%E6%84%8F%E6%80%9D%7E%E6%89%93%E9%94%99%E4%BA%86)
f(x)=sin^2wx+√s sinwxsin(wx+π/2) (w>0) 最小正周期为π.1)求w值;2)求函数f(x)在[0,2π/3]上值域√3~不好意思~打错了
f(x)=sin^2wx+√s sinwxsin(wx+π/2) (w>0) 最小正周期为π.
1)求w值;
2)求函数f(x)在[0,2π/3]上值域
√3~不好意思~打错了
f(x)=sin^2wx+√s sinwxsin(wx+π/2) (w>0) 最小正周期为π.1)求w值;2)求函数f(x)在[0,2π/3]上值域√3~不好意思~打错了
lz确定是√s,不是√3
提示,后面是的sinwx*coswx=0.5√3sin2wx
sin^2wx=0.5-0.5*cos2wx
接下来应该好做了吧?
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