有关复数的题目一.计算:1) 根根根(-1),并作出图形.2) [12(cos7π/4+isin7π/4)]/[6(cos2π/3+isin2π/3)]3) [(根3)(cos150度+isin150度)]/[(根2)(cos225度+isin225度)]4) 2/(cosπ/4+isinπ/4)5) -i/[2(cos120度+isin120度)]二.解方程:x^
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/19 22:51:57
![有关复数的题目一.计算:1) 根根根(-1),并作出图形.2) [12(cos7π/4+isin7π/4)]/[6(cos2π/3+isin2π/3)]3) [(根3)(cos150度+isin150度)]/[(根2)(cos225度+isin225度)]4) 2/(cosπ/4+isinπ/4)5) -i/[2(cos120度+isin120度)]二.解方程:x^](/uploads/image/z/8648781-69-1.jpg?t=%E6%9C%89%E5%85%B3%E5%A4%8D%E6%95%B0%E7%9A%84%E9%A2%98%E7%9B%AE%E4%B8%80.%E8%AE%A1%E7%AE%97%3A1%29+%E6%A0%B9%E6%A0%B9%E6%A0%B9%28-1%29%2C%E5%B9%B6%E4%BD%9C%E5%87%BA%E5%9B%BE%E5%BD%A2.2%29+%5B12%28cos7%CF%80%2F4%2Bisin7%CF%80%2F4%29%5D%2F%5B6%28cos2%CF%80%2F3%2Bisin2%CF%80%2F3%29%5D3%29+%5B%28%E6%A0%B93%29%28cos150%E5%BA%A6%2Bisin150%E5%BA%A6%29%5D%2F%5B%28%E6%A0%B92%29%28cos225%E5%BA%A6%2Bisin225%E5%BA%A6%29%5D4%29+2%2F%28cos%CF%80%2F4%2Bisin%CF%80%2F4%295%29+-i%2F%5B2%28cos120%E5%BA%A6%2Bisin120%E5%BA%A6%29%5D%E4%BA%8C.%E8%A7%A3%E6%96%B9%E7%A8%8B%3Ax%5E)
有关复数的题目一.计算:1) 根根根(-1),并作出图形.2) [12(cos7π/4+isin7π/4)]/[6(cos2π/3+isin2π/3)]3) [(根3)(cos150度+isin150度)]/[(根2)(cos225度+isin225度)]4) 2/(cosπ/4+isinπ/4)5) -i/[2(cos120度+isin120度)]二.解方程:x^
有关复数的题目
一.计算:
1) 根根根(-1),并作出图形.
2) [12(cos7π/4+isin7π/4)]/[6(cos2π/3+isin2π/3)]
3) [(根3)(cos150度+isin150度)]/[(根2)(cos225度+isin225度)]
4) 2/(cosπ/4+isinπ/4)
5) -i/[2(cos120度+isin120度)]
二.解方程:
x^5+x^4+x^3+x^2+x+1=0 (x全属于C)
三.求证
1/(cosθ+isinθ)=cosθ-isinθ
四.求下列复数z的倒数1/z的模与辐角
1) z=4(cosπ/12+isinπ/12)
2) z=cosπ/6-isinπ/6
3) [(根2)/2]*(1-i)
有关复数的题目一.计算:1) 根根根(-1),并作出图形.2) [12(cos7π/4+isin7π/4)]/[6(cos2π/3+isin2π/3)]3) [(根3)(cos150度+isin150度)]/[(根2)(cos225度+isin225度)]4) 2/(cosπ/4+isinπ/4)5) -i/[2(cos120度+isin120度)]二.解方程:x^
如图,打那太吃力了,你才零分能给你这么打不错了.已更新
1.如果复数z满足|z+1|=|z-i|,那么|z+i|的最小值是