跪求高数高手解答; 1、f(x)=x^2,求f'(f'(x))=? (要具体步骤) 2、x^2对2x求导=?,x^2对1/2x求导=?
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![跪求高数高手解答; 1、f(x)=x^2,求f'(f'(x))=? (要具体步骤) 2、x^2对2x求导=?,x^2对1/2x求导=?](/uploads/image/z/8915954-50-4.jpg?t=%E8%B7%AA%E6%B1%82%E9%AB%98%E6%95%B0%E9%AB%98%E6%89%8B%E8%A7%A3%E7%AD%94%EF%BC%9B+1%E3%80%81f%28x%29%3Dx%5E2%2C%E6%B1%82f%27%28f%27%28x%29%29%3D%3F+%EF%BC%88%E8%A6%81%E5%85%B7%E4%BD%93%E6%AD%A5%E9%AA%A4%EF%BC%89+2%E3%80%81x%5E2%E5%AF%B92x%E6%B1%82%E5%AF%BC%3D%3F%2Cx%5E2%E5%AF%B91%2F2x%E6%B1%82%E5%AF%BC%3D%3F)
跪求高数高手解答; 1、f(x)=x^2,求f'(f'(x))=? (要具体步骤) 2、x^2对2x求导=?,x^2对1/2x求导=?
跪求高数高手解答; 1、f(x)=x^2,求f'(f'(x))=? (要具体步骤) 2、x^2对2x求导=?,x^2对1/2x求导=?
跪求高数高手解答; 1、f(x)=x^2,求f'(f'(x))=? (要具体步骤) 2、x^2对2x求导=?,x^2对1/2x求导=?
1、f'(x)=2x所以,f(f'(x))=2(2x)=4x,f'(f'(x))=4
2、d(x^2)/d(2x)=(2xdx)/(2dx)=x
d(x^2)/d(1/2x)=(2xdx)/{[-1/(2x^2)]dx}=-4x^3
f'(x)=2x f'(f'(x))=f'(2x)=4x d(x^2)/d(2x)=2xdx/2dx=x d(x^2)/d(x/2)=2xdx/[(1/2)dx]=4x最终答案是4x!我就是概念和求导顺序搞不清楚,然后你算的我看不清楚。我觉得这题是不是先 f'(x)=2x f'(f'(x))=f'(2x)=d4x^2/d2x=8xdx/2dx=4x(是不是跟你算理一样?) 您觉得是否有算理...
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f'(x)=2x f'(f'(x))=f'(2x)=4x d(x^2)/d(2x)=2xdx/2dx=x d(x^2)/d(x/2)=2xdx/[(1/2)dx]=4x
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1 f’(x)=(x^2)’=2x;
f(f’(x))=f(2x)=(2x)^2=4x^2;
f’(f’(x))=f’(4x^2)=8x
2 x^2=1/4*(2x)^2;d (x^2)/ d(2x) = d (1/4*(2x)^2)/ d(2x) = d (1/4*t^2)/ dt=2t=x;
...
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1 f’(x)=(x^2)’=2x;
f(f’(x))=f(2x)=(2x)^2=4x^2;
f’(f’(x))=f’(4x^2)=8x
2 x^2=1/4*(2x)^2;d (x^2)/ d(2x) = d (1/4*(2x)^2)/ d(2x) = d (1/4*t^2)/ dt=2t=x;
x^2=4*(x/2)^2; d (x^2)/ d(x/2)= d(4*(x/2)^2)/ d(x/2)= d (4*t2)/ d t=8t=4x;
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f’(x)=(x^2)’=2x f(f’(x))=f(2x)=(2x)^2=4x^2 f’(f’(x))=f’(4x^2)=8x