1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)一定要详细的不能在详细.第二道题中的·那个8打错了应去掉
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![1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)一定要详细的不能在详细.第二道题中的·那个8打错了应去掉](/uploads/image/z/8934449-41-9.jpg?t=1.log2+3%2Alog3+4%2Alog4+5%2Alog5+2+2.%28log4+3%2Blog8+3%298%28log3+2%2Blog9+2%29%E4%B8%80%E5%AE%9A%E8%A6%81%E8%AF%A6%E7%BB%86%E7%9A%84%E4%B8%8D%E8%83%BD%E5%9C%A8%E8%AF%A6%E7%BB%86.%E7%AC%AC%E4%BA%8C%E9%81%93%E9%A2%98%E4%B8%AD%E7%9A%84%C2%B7%E9%82%A3%E4%B8%AA8%E6%89%93%E9%94%99%E4%BA%86%E5%BA%94%E5%8E%BB%E6%8E%89)
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)一定要详细的不能在详细.第二道题中的·那个8打错了应去掉
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)
一定要详细的不能在详细.
第二道题中的·那个8打错了应去掉
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 2)一定要详细的不能在详细.第二道题中的·那个8打错了应去掉
1、log2 3*log3 4*log4 5*log5 2
=lg2/lg3xlg3/lg4xlg4/lg5xlg5/lg2 (换底公式)
=1 (约分)
2.(log4 3+log8 3)*(log3 2+log9 2) 中间应为乘号
=(lg3/lg4+lg3/lg8)*(lg2/lg3+lg2/lg9)
=(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)
=[(1/2+1/3)(lg3/lg2)]*[(1+1/2)(lg2/lg3)]
=(1/2+1/3)*(1+1/2)
=5/6*3/2
=5/4
答:换底公式等
1)
log2 3*log3 4*log4 5*log5 2
=log2(3)×log3(4)×log4(5)×log5(2)
=(lg3/lg2)×(lg4/lg3)×(lg5/lg4)×(lg2/lg5)
=1
2)
(log4 3+log8 3)*(log3 2+log9 2
=[ log4(3)+log8(3...
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答:换底公式等
1)
log2 3*log3 4*log4 5*log5 2
=log2(3)×log3(4)×log4(5)×log5(2)
=(lg3/lg2)×(lg4/lg3)×(lg5/lg4)×(lg2/lg5)
=1
2)
(log4 3+log8 3)*(log3 2+log9 2
=[ log4(3)+log8(3)] ×[log3(2)+log9(2)]
=[log2(3)/log2(4)+log2(3)/log2(8)]×(lg2/lg3+lg2/lg9)
=[ log2(3) ]×(1/2+1/3)×(lg2/lg3)×(1+1/2)
=(5/6)×(3/2)×[lg3/lg2]×(lg2/lg3)
=5/4
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