if a 1500kg car moving with velocity of 50m/s is suddenly decelerate to a stop.its acceleration during this period is -10m/s2,and it takes 50m for the the car come to a complete stop.the coefficient of the friction is 0.8.if i want to calculate the f
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 07:25:18
![if a 1500kg car moving with velocity of 50m/s is suddenly decelerate to a stop.its acceleration during this period is -10m/s2,and it takes 50m for the the car come to a complete stop.the coefficient of the friction is 0.8.if i want to calculate the f](/uploads/image/z/9815005-37-5.jpg?t=if+a+1500kg+car+moving+with+velocity+of+50m%2Fs+is+suddenly+decelerate+to+a+stop.its+acceleration+during+this+period+is+-10m%2Fs2%2Cand+it+takes+50m+for+the+the+car+come+to+a+complete+stop.the+coefficient+of+the+friction+is+0.8.if+i+want+to+calculate+the+f)
if a 1500kg car moving with velocity of 50m/s is suddenly decelerate to a stop.its acceleration during this period is -10m/s2,and it takes 50m for the the car come to a complete stop.the coefficient of the friction is 0.8.if i want to calculate the f
if a 1500kg car moving with velocity of 50m/s is suddenly decelerate to a stop.its acceleration during this period is -10m/s2,and it takes 50m for the the car come to a complete stop.the coefficient of the friction is 0.8.
if i want to calculate the force of the friction,which formula should i use?F=Ma or f=N*µ?why?what's the difference?will these two results come up to be the same?(i make up those data)
if a 1500kg car moving with velocity of 50m/s is suddenly decelerate to a stop.its acceleration during this period is -10m/s2,and it takes 50m for the the car come to a complete stop.the coefficient of the friction is 0.8.if i want to calculate the f
问题很简单.两个公式的应用条件是不同的,第一个是牛顿第二定律的表达式,力为物体在运动的过程中受到的合外力,加速度是合加速度.用此公式去此题结果是15000N.而第二个公式是第三章学的求摩擦力的公式,此公式中的力N是两物体间的正压力,重力是竖直向下的而此时两物体间的正压力不一定是物体受到的重力.所以本人认为应该应用牛顿运动定律解本题比较好.
……英语问题吧……