将BaSO4和PbSO4固体加入到PH=2.5的HNO3溶液中,待其达到溶解平衡后,试液中SO42-的总浓度为多少?(Ksp(BaSO4)=1.1*10-10,Ksp(PbSO4)=1.6*10-8,H2SO4的Ka2=1*10-2)
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![将BaSO4和PbSO4固体加入到PH=2.5的HNO3溶液中,待其达到溶解平衡后,试液中SO42-的总浓度为多少?(Ksp(BaSO4)=1.1*10-10,Ksp(PbSO4)=1.6*10-8,H2SO4的Ka2=1*10-2)](/uploads/image/z/9943990-70-0.jpg?t=%E5%B0%86BaSO4%E5%92%8CPbSO4%E5%9B%BA%E4%BD%93%E5%8A%A0%E5%85%A5%E5%88%B0PH%EF%BC%9D2.5%E7%9A%84HNO3%E6%BA%B6%E6%B6%B2%E4%B8%AD%2C%E5%BE%85%E5%85%B6%E8%BE%BE%E5%88%B0%E6%BA%B6%E8%A7%A3%E5%B9%B3%E8%A1%A1%E5%90%8E%2C%E8%AF%95%E6%B6%B2%E4%B8%ADSO42-%E7%9A%84%E6%80%BB%E6%B5%93%E5%BA%A6%E4%B8%BA%E5%A4%9A%E5%B0%91%3F%EF%BC%88Ksp%28BaSO4%29%3D1.1%2A10-10%2CKsp%28PbSO4%29%3D1.6%2A10-8%2CH2SO4%E7%9A%84Ka2%3D1%2A10-2%EF%BC%89)
将BaSO4和PbSO4固体加入到PH=2.5的HNO3溶液中,待其达到溶解平衡后,试液中SO42-的总浓度为多少?(Ksp(BaSO4)=1.1*10-10,Ksp(PbSO4)=1.6*10-8,H2SO4的Ka2=1*10-2)
将BaSO4和PbSO4固体加入到PH=2.5的HNO3溶液中,待其达到溶解平衡后,试液中SO42-的总浓度为多少?
(Ksp(BaSO4)=1.1*10-10,Ksp(PbSO4)=1.6*10-8,H2SO4的Ka2=1*10-2)
将BaSO4和PbSO4固体加入到PH=2.5的HNO3溶液中,待其达到溶解平衡后,试液中SO42-的总浓度为多少?(Ksp(BaSO4)=1.1*10-10,Ksp(PbSO4)=1.6*10-8,H2SO4的Ka2=1*10-2)
设平衡后溶液中Ba2+浓度为x,Pb2+浓度为y,SO42-浓度为z,则HSO4-的浓度为(x+y-z),
与SO42-结合的H+浓度也为(x+y-z),所以溶液中剩余H+浓度为10^-2.5-(x+y-z).
BaSO4(s) ⇋ Ba2+ + SO42-
Ksp(BaSO4)=[Ba2+][SO42-]=x*z=1.1*10^-10
PbSO4(s) ⇋ Pb2+ + SO42- Ksp(PbSO4)=[Pb2+][SO42-]=y*z=1.6*10^-8
HSO4- ⇋ SO42- + H+ Ka2=[HSO4-]/([H+][SO42-])=(x+y-z)/{[10^-2.5-(x+y-z)]*z}=1*10^-2
由上述三个方程求解x,y,z即可,z即SO42-的总浓度.
题目的数据是否齐全?