在平面直角坐标系中,左焦点为F1(-1,0),P为椭圆G的上顶点,且∠PF1O=45°.解析理由看不懂的?网上查的解析中这里看不懂啊?AB|² = (x₁ - x₂)² + (y₁ - y₂)² = (x₁ - x₂)
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![在平面直角坐标系中,左焦点为F1(-1,0),P为椭圆G的上顶点,且∠PF1O=45°.解析理由看不懂的?网上查的解析中这里看不懂啊?AB|² = (x₁ - x₂)² + (y₁ - y₂)² = (x₁ - x₂)](/uploads/image/z/1832548-4-8.jpg?t=%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E5%B7%A6%E7%84%A6%E7%82%B9%E4%B8%BAF1%28-1%2C0%29%2CP%E4%B8%BA%E6%A4%AD%E5%9C%86G%E7%9A%84%E4%B8%8A%E9%A1%B6%E7%82%B9%2C%E4%B8%94%E2%88%A0PF1O%3D45%C2%B0.%E8%A7%A3%E6%9E%90%E7%90%86%E7%94%B1%E7%9C%8B%E4%B8%8D%E6%87%82%E7%9A%84%3F%E7%BD%91%E4%B8%8A%E6%9F%A5%E7%9A%84%E8%A7%A3%E6%9E%90%E4%B8%AD%E8%BF%99%E9%87%8C%E7%9C%8B%E4%B8%8D%E6%87%82%E5%95%8A%3FAB%7C%26%23178%3B+%3D+%28x%26%238321%3B+-+x%26%238322%3B%29%26%23178%3B+%2B+%28y%26%238321%3B+-+y%26%238322%3B%29%26%23178%3B+%3D+%28x%26%238321%3B+-+x%26%238322%3B%29%26%231)
在平面直角坐标系中,左焦点为F1(-1,0),P为椭圆G的上顶点,且∠PF1O=45°.解析理由看不懂的?网上查的解析中这里看不懂啊?AB|² = (x₁ - x₂)² + (y₁ - y₂)² = (x₁ - x₂)
在平面直角坐标系中,左焦点为F1(-1,0),P为椭圆G的上顶点,且∠PF1O=45°.解析理由看不懂的?
网上查的解析中这里看不懂啊?AB|² = (x₁ - x₂)² + (y₁ - y₂)² = (x₁ - x₂)² + (kx₁ + m₁ - ky₂ - m₁)²
= (k² + 1)(x₁ - x₂)²
还有这里S = (4√2)m₁√(2- m₁²)
S' = (4√2)[√(2- m₁²) - m₁(1/2)(-2m₁)/√(2- m₁²)]
= (4√2)[(2- 2m₁²)/√(2- m₁²)] = 0,求详细解答?急!
在平面直角坐标系中,左焦点为F1(-1,0),P为椭圆G的上顶点,且∠PF1O=45°.解析理由看不懂的?网上查的解析中这里看不懂啊?AB|² = (x₁ - x₂)² + (y₁ - y₂)² = (x₁ - x₂)
AB|² = (x₁ - x₂)² + (y₁ - y₂)²(这是两点间的距离公式) = (x₁ - x₂)² + (kx₁ + m₁ - ky₂ - m₁)²(此是把挨了1的方程代入进去了)S = (4√2)m₁√(2- m₁²)
S' = (4√2)[√(2- m₁²) - m₁(1/2)(-2m₁)/√(2- m₁²)],S'应该也是某个图形的面积,但具体是哪个面积你却未告知!你还是仔细查看一下解答吧!
= (4√2)[(2- 2m₁²)/√(2- m₁²)] = 0,S是所求的面积
= (k² + 1)(x₁ - x₂)²